Using the results from Bader to calculate dipole moment of water
Posted: Sat Sep 03, 2016 12:16 pm
Dear all,
I tried to use the Bader analysis via VASP to repeat the results of the given example (H2O gaussian cube). I got the charge for H is 0.4254e, which does not agree with the value in the example (0.365e). Then I check the ACF.dat in the example and find the the X Y Z coordinate positions seem not to be in the right place of a real H2O (the distance between H and O is much larger than 1 Angstrom), while my OH bond distance is calculated to be 0.972 angstrom. Am I WRONG? I can't understand that.
Another question is that after I got the charge of H, i.e. 0.42 e, then can I use this value to calculate the dipole moment of H2O? It seems that definitely not. If not, then how can I utilize the bader analysis to get the "effective net charge ", saying similar to an experimental value of "ca. 0.33e"?
Can someone tell me how to do that?
Regards!
I tried to use the Bader analysis via VASP to repeat the results of the given example (H2O gaussian cube). I got the charge for H is 0.4254e, which does not agree with the value in the example (0.365e). Then I check the ACF.dat in the example and find the the X Y Z coordinate positions seem not to be in the right place of a real H2O (the distance between H and O is much larger than 1 Angstrom), while my OH bond distance is calculated to be 0.972 angstrom. Am I WRONG? I can't understand that.
Another question is that after I got the charge of H, i.e. 0.42 e, then can I use this value to calculate the dipole moment of H2O? It seems that definitely not. If not, then how can I utilize the bader analysis to get the "effective net charge ", saying similar to an experimental value of "ca. 0.33e"?
Can someone tell me how to do that?
Regards!