Bader charge vs. oxidation state
Posted: Sun Apr 12, 2015 9:52 pm
Hello
I am currently working on a research project aiming at determining oxidation state of metallic atoms in a metal oxide material.
To reach this goal, I performed a Bader analysis on my system as described in the website http://theory.cm.utexas.edu/henkelman/code/bader/
However I observed that various metallic atoms, that are expected to have different oxidation states, have very close Bader charge.
For example, all the Ni oxidation states (0, I, II, III or IV) have Bader charges in the range 1.2-1.3
Thus, it seems that Bader analysis is not an efficient tool to discriminate between several oxidation state.
What is your advice?
I would like to know in particular:
1- What is the difference between Bader charge and oxidation state? Are those 2 concepts similar?
2- How to deduce oxidation state for Bader analysis?
3- What is the correct procedure to compute oxidation state of an atom? Shall one also consider other parameters such as Magnetization of Mulliken charge?
Thanks for your help
Jeremie
I am currently working on a research project aiming at determining oxidation state of metallic atoms in a metal oxide material.
To reach this goal, I performed a Bader analysis on my system as described in the website http://theory.cm.utexas.edu/henkelman/code/bader/
However I observed that various metallic atoms, that are expected to have different oxidation states, have very close Bader charge.
For example, all the Ni oxidation states (0, I, II, III or IV) have Bader charges in the range 1.2-1.3
Thus, it seems that Bader analysis is not an efficient tool to discriminate between several oxidation state.
What is your advice?
I would like to know in particular:
1- What is the difference between Bader charge and oxidation state? Are those 2 concepts similar?
2- How to deduce oxidation state for Bader analysis?
3- What is the correct procedure to compute oxidation state of an atom? Shall one also consider other parameters such as Magnetization of Mulliken charge?
Thanks for your help
Jeremie