NEB computation for CH3O + H reaction
Posted: Wed Feb 20, 2013 2:54 am
Dear everyone,
I want to compute the reaction barrier of reaction CH3O + H --> CH3OH on Cu(111) surface in order to reproduce others work. I adopt 6 images and firstly converge with the setup:
IOPT=7, timestep=0.01, EDIFFG = -0.1, ENCUT = 300, PREC = normal (decrease computation cost)
after convergence, continue computation with IOPT = 1, MAXMOVE=0.1, but due to the slow convergence of image 4, the job is hang on, cannot proceed to the next step. The following is the nebef.pl results:
0 0.00000000 -122.40063000 0.00000000
1 0.57161200 -122.41354100 -0.01291100
2 2.22259100 -121.89552700 0.50510300
3 1.59835100 -121.19520000 1.20543000
4 1.77959600 -119.83122700 2.56940300
5 0.77448400 -122.22481500 0.17581500
6 0.47699900 -122.37618800 0.02444200
7 0.00000000 -122.52369200 -0.12306200
The attachment is the movie file named rtH3COH-1-281-0220.rar obtained by nebmovie.pl. Could anyone give comments to this path? How to modify the path? Any advice is appreciated, thank you very much.
Jingbo
I want to compute the reaction barrier of reaction CH3O + H --> CH3OH on Cu(111) surface in order to reproduce others work. I adopt 6 images and firstly converge with the setup:
IOPT=7, timestep=0.01, EDIFFG = -0.1, ENCUT = 300, PREC = normal (decrease computation cost)
after convergence, continue computation with IOPT = 1, MAXMOVE=0.1, but due to the slow convergence of image 4, the job is hang on, cannot proceed to the next step. The following is the nebef.pl results:
0 0.00000000 -122.40063000 0.00000000
1 0.57161200 -122.41354100 -0.01291100
2 2.22259100 -121.89552700 0.50510300
3 1.59835100 -121.19520000 1.20543000
4 1.77959600 -119.83122700 2.56940300
5 0.77448400 -122.22481500 0.17581500
6 0.47699900 -122.37618800 0.02444200
7 0.00000000 -122.52369200 -0.12306200
The attachment is the movie file named rtH3COH-1-281-0220.rar obtained by nebmovie.pl. Could anyone give comments to this path? How to modify the path? Any advice is appreciated, thank you very much.
Jingbo